-k^2-11k-8=0

Solution for -k^2-11k-8=0 equation:

-k^2-11k-8=0

We add all the numbers together, and all the variables

-1k^2-11k-8=0

a = -1; b = -11; c = -8;
Δ = b2-4ac
Δ = -112-4·(-1)·(-8)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{89}}{2*-1}=\frac{11-\sqrt{89}}{-2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{89}}{2*-1}=\frac{11+\sqrt{89}}{-2}
$